Sesquilinear form

In, a sesquilinear form is a generalization of a that, in turn, is a generalization of the concept of the  of. A bilinear form is in each of its arguments, but a sesquilinear form allows one of the arguments to be "twisted" in a  manner, thus the name; which originates from the Latin   meaning "one and a half". The basic concept of the dot product – producing a from a pair of vectors – can be generalized by allowing a broader range of scalar values and, perhaps simultaneously, by widening the definition of what a vector is.

A motivating special case is a sesquilinear form on a, $V$. This is a map $V × V → C$ that is linear in one argument and "twists" the linearity of the other argument by (referred to as being  in the other argument). This case arises naturally in mathematical physics applications. Another important case allows the scalars to come from any and the twist is provided by a.

An application in requires that the scalars come from a  (skewfield), $K$, and this means that the "vectors" should be replaced by elements of a. In a very general setting, sesquilinear forms can be defined over $K$-modules for arbitrary $R$.

Convention
Conventions differ as to which argument should be linear. In the commutative case, we shall take the first to be linear, as is common in the mathematical literature, except in the section devoted to sesquilinear forms on complex vector spaces. There we use the other convention and take the first argument to be conjugate-linear (i.e. antilinear) and the second to be linear. This is the convention used mostly by mathematical physicists and originates in  in.

In the more general noncommutative setting, with right modules we take the second argument to be linear and with left modules we take the first argument to be linear.

Complex vector spaces
Over a $R$ a map $V$ is sesquilinear if
 * $$\begin{align}

&\varphi(x + y, z + w) = \varphi(x, z) + \varphi(x, w) + \varphi(y, z) + \varphi(y, w)\\ &\varphi(a x, b y) = \overline{a}b\,\varphi(x,y)\end{align}$$ for all $V × V → C$ and all $V$. $φ : V × V → C$ is the complex conjugate of $x, y, z, w ∈ V$.

A complex sesquilinear form can also be viewed as a complex
 * $$\overline{V} \times V \to \mathbf{C} $$

where $a, b ∈ C$ is the to $\overline{a}$. By the of s these are in one-to-one correspondence with complex linear maps
 * $$\overline{V} \otimes V \to \mathbf{C}.$$

For a fixed $a$ in $\overline{V}$ the map $V$ is a on $z$ (i.e. an element of the  $V$). Likewise, the $w ↦ φ(z, w)$ is a  on $V$.

Given any complex sesquilinear form $V^{∗}$ on $w ↦ φ(w, z)$ we can define a second complex sesquilinear form $V$ via the :
 * $$\psi(w,z) = \overline{\varphi(z,w)}.$$

In general, $φ$ and $V$ will be different. If they are the same then $ψ$ is said to be Hermitian. If they are negatives of one another, then $ψ$ is said to be skew-Hermitian. Every sesquilinear form can be written as a sum of a Hermitian form and a skew-Hermitian form.

Matrix representation
If $φ$ is a finite-dimensional complex vector space, then relative to any $φ$ of $φ$, a sesquilinear form is represented by a  $V$, ${ e_{i} }$ by the column vector $V$, and $Φ$ by the column vector $w$:
 * $$\varphi(w,z) = \varphi \left(\sum_i w_i e_i, \sum_j z_j e_j \right) = \sum_i \sum_j \overline{w_i} z_j \varphi(e_i, e_j) = {\overline{\mathbf{w}}}^\mathrm{T} \mathbf{\Phi} \mathbf{z} .$$

The components of $w$ are given by $z$.

Hermitian form

 * The term Hermitian form may also refer to a different concept than that explained below: it may refer to a certain on a .

A complex Hermitian form (also called a symmetric sesquilinear form), is a sesquilinear form $z$ such that
 * $$h(w,z) = \overline{h(z, w)}.$$

The standard Hermitian form on $Φ$ is given (again, using the "physics" convention of linearity in the second and conjugate linearity in the first variable) by
 * $$\langle w,z \rangle = \sum_{i=1}^n \overline{w_i} z_i.$$

More generally, the on any complex  is a Hermitian form.

A minus sign is introduced in the Hermitian form $$w w^* - z z^*$$  to define the group.

A vector space with a Hermitian form $Φ_{ij} = φ(e_{i}, e_{j})$ is called a Hermitian space.

The matrix representation of a complex Hermitian form is a.

A complex Hermitian form applied to a single vector
 * $$|z|_h = h(z, z)$$

is always. One can show that a complex sesquilinear form is Hermitian the associated quadratic form is real for all $h : V × V → C$.

Skew-Hermitian form
A complex skew-Hermitian form (also called an antisymmetric sesquilinear form), is a complex sesquilinear form $C^{n}$ such that
 * $$s(w,z) = -\overline{s(z, w)}.$$

Every complex skew-Hermitian form can be written as times a Hermitian form.

The matrix representation of a complex skew-Hermitian form is a.

A complex skew-Hermitian form applied to a single vector
 * $$|z|_s = s(z, z)$$

is always pure.

Over a division ring
This section applies unchanged when the division ring $(V, h)$ is commutative. More specific terminology then also applies: the division ring is a field, the anti-automorphism is also an automorphism, and the right module is a vector space. The following applies to a left module with suitable reordering of expressions.

Definition
A $z ∈ V$-sesquilinear form over a right $s : V × V → C$-module $i$ is a $K$ with an associated  $σ$ of a  $K$ such that, for all $M$ and all $φ : M × M → K$,
 * $$\varphi(x \alpha, y \beta) = \sigma(\alpha) \, \varphi(x, y) \, \beta .$$

The associated anti-automorphism $σ$ for any nonzero sesquilinear form $K$ is uniquely determined by $x, y ∈ M$.

Orthogonality
Given a sesquilinear form $α, β ∈ K$ over a module $σ$ and a subspace $φ$ of $φ$, the orthogonal complement of $φ$ with respect to $M$ is
 * $$W^{\perp}=\{\mathbf{v} \in M \mid \varphi (\mathbf{v}, \mathbf{w})=0,\ \forall \mathbf{w}\in W\} . $$

Similarly, $W$ is orthogonal to $M$ with respect to $W$, written $φ$ (or simply $x ∈ M$ if $y ∈ M$ can be inferred from the context), when $φ$. This need not be, i.e. $x ⊥_{φ} y$ does not imply $x ⊥ y$ (but see  below).

Reflexivity
A sesquilinear form $φ$ is reflexive if, for all $φ(x, y) = 0$,
 * $$\varphi(x, y) = 0$$ implies $$\varphi(y, x) = 0 .$$

That is, a sesquilinear form is reflexive precisely when the derived orthogonality relation is symmetric.

Hermitian variations
A $x ⊥ y$-sesquilinear form $y ⊥ x$ is called $φ$-Hermitian if there exists $x, y ∈ M$ such that, for all $σ$,
 * $$\varphi(x, y) = \sigma ( \varphi (y, x)) \, \varepsilon .$$

If $φ$, the form is called $(σ, ε)$-Hermitian, and if $ε ∈ K$, it is called $x, y ∈ M$-anti-Hermitian. (When $ε = 1$ is implied, respectively simply Hermitian or anti-Hermitian.)

For a nonzero $σ$-Hermitian form, it follows that, for all $ε = −1$,
 * $$ \sigma ( \varepsilon ) = \varepsilon^{-1} $$
 * $$ \sigma ( \sigma ( \alpha ) ) = \varepsilon \alpha \varepsilon^{-1} .$$

It also follows that $σ$ is a of the map $σ$. The fixed points of this map from a of the  of $(σ, ε)$.

A $α ∈ K$-Hermitian form is reflexive, and every reflexive $φ(x, x)$-sesquilinear form is $α ↦ σ(α)ε$-Hermitian for some $K$.

In the special case that $(σ, ε)$ is the (i.e., $σ$), $(σ, ε)$ is commutative, $ε$ is a bilinear form and $σ$. Then for $σ = id$ the bilinear form is called symmetric, and for $K$ is called skew-symmetric.

Example
Let $φ$ be the three dimensional vector space over the $ε^{2} = 1$, where $ε = 1$ is a. With respect to the standard basis we can write $ε = −1$ and ${ e_{i} }$ and define the map $V$ by:
 * $$\varphi(x, y) = x_1 y_1{}^q + x_2 y_2{}^q + x_3 y_3{}^q.$$

The map $φ$ is an involutory automorphism of $V$. The map $M_{φ}$ is then a $F$-sesquilinear form. The matrix $V^{∗}$ associated to this form is the. This is a Hermitian form.

In projective geometry
In a $V$, a  $V$ of the subspaces that inverts inclusion, i.e.
 * $F = GF(q^{2})$ for all subspaces $q$, $x = (x_{1}, x_{2}, x_{3})$ of $y = (y_{1}, y_{2}, y_{3})$,

is called a. A result of Birkhoff and von Neumann (1936) shows that the correlations of projective geometries correspond to the nondegenerate sesquilinear forms on the underlying vector space. A sesquilinear form $φ$ is nondegenerate if $σ : t ↦ t^{q}$ for all $F$ in $φ$ (if and) only if $σ$.

To achieve full generality of this statement, and since every desarguesian projective geometry may be coordinatized by a, extended the definition of a sesquilinear form to a division ring, which requires replacing vector spaces by s. (In the geometric literature these are still referred to as either left or right vector spaces over skewfields.)

Over arbitrary rings
The specialization of the above section to skewfields was a consequence of the application to projective geometry, and not intrinsic to the nature of sesquilinear forms. Only the minor modifications needed to take into account the non-commutativity of multiplication are required to generalize the arbitrary field version of the definition to arbitrary rings.

Let $M_{φ}$ be a ring, $G$ an $δ$-module and $S ⊆ T ⇒ T^{δ} ⊆ S^{δ}$ an of $S$.

A map $T$ is $G$-sesquilinear if
 * $$\varphi(x + y, z + w) = \varphi(x, z) + \varphi(x, w) + \varphi(y, z) + \varphi(y, w)$$
 * $$\varphi(c x, d y) = c \, \varphi(x,y) \, \sigma(d)$$

for all $φ$ and all $φ(x, y) = 0$.

An element $y$ is orthogonal to another element $V$ with respect to the sesquilinear form $x = 0$ (written $R$) if $A$. This relation need not be symmetric, i.e. $F$ does not imply $α$.

A sesquilinear form $F$ is reflexive (or orthosymmetric) if $f : A × A → F$ implies $a, b, c ∈ A$ for all $f(a + b, c) = f(a, c) + f(b, c)$.

A sesquilinear form $f(a, b + c) = f(a, b) + f(a, c)$ is Hermitian if there exists $t ∈ F$ such that
 * $$\varphi(x, y) = \sigma(\varphi(y, x))$$

for all $x, y ∈ A$. A Hermitian form is necessarily reflexive, and if it is nonzero, the associated antiautomorphism $f(tx, y) = tf(x, y)$ is an involution (i.e. of order 2).

Since for an antiautomorphism $f(x, ty) = f(x, y) t^{α}$ we have $t ↦ t^{α}$ for all $α$ in $A$, if $α$, then $α$ must be commutative and $f$ is a bilinear form. In particular, if, in this case, $α$ is a skewfield, then $ε$ is a field and $ε = ±1$ is a vector space with a bilinear form.

An antiautomorphism $R$ can also be viewed as an isomorphism of $V$, the opposite ring based on the same set with the same addition, but whose multiplication operation ($R$) is defined by $σ$, where the product on the right is the product in $R$. It follows from this that a right (left) $φ : V × V → R$-module $σ$ can be turned into a left (right) $x, y, z, w ∈ V$-module, $c, d ∈ R$. Thus, the sesquilinear form $x$ can be viewed as a bilinear form $y$.